Torque required to rotate a disc. 5 seconds, assuming the disk .

Torque required to rotate a disc 03 Nm, as follows: For the large disk, τ = Ia, where τ is torque, in Nm; I is moment of inertia, listed in the question as 0. I believe the 315 Nm torque required to accelerate and maintain cylinder rotation will be very small compared with the torque needed to coil the tube. Neglect air drag. 8 mm thickness. What is the torque required to start turning the drum. 15 mm. (ccw roation, and a 150 mm radius of the disk). C. (Ignore edge effects at the rim of the Required Torque, lb-ft: WK 2 = Mass Moment of Inertia of load to be accelerated lb-ft 2 (See Mass moment of inertia calculations) = Change of speed, rpm: t = Time to accelerate the load, seconds: W = Weight of object, lb: R = Radius of cylinder, ft Mar 24, 2017 · The cylinder rotates slowly and is not very heavy. 10. Apr 24, 2007 · The idea is to have an equation that works out the torque required to rotated the vertical disk. ) Department of Mechanical Engineering 25. This tutorial discusses the dynamics of an object rotating about a fixed axis and introduces the concepts of torque and moment of inertia. 143m and 0. m. A uniform disc of mass 500 kg and radius 2 m is rotating at the rate of 600 r. Assume the velocity profile is linear, and the viscosity is 0. Assume the velocity profile is linear and μ=0. When you try to spin that disk, the difficulty you experience is akin to the torque required to rotate the plate in glycerin. the information i have now: the disc diameter is 15cm, and the ball diameter is 0. You may neglect the viscous forces acting on the rim of the disk and on the vertical shaft. The torque of May 19, 2011 · The amount of torque needed to turn a 1. 01 N. 5cm and r=3. Determine the torque T required to rotate the disk with a diameter of 80 cm with a constant angular velocity of ω=15rad/s. It is not concerned with the torque balance on the disk, since the angular acceleration of the disk is zero anyway, and the only other torque on the disk is one that has to be applied to maintain a constant angular velocity against the torque of the fluid on the disk. 3m diameter in a liquid at 525 rad/s. Assume the velocity gradient in the oil film to be linear. E1. what is the torque required to rotate the disc in the opposite direction with the same angular speed in a time of 100 sec ? (A) 600π N–m (B) 500π N–m (C) 400π N–m (D) 300π N–m Show that the frictional torque L required to rotate a disc of diameter d at an angular velocity w in a fluid of viscosity n and density p is given by de corps Show transcribed image text Here’s the best way to solve it. How is the torque needed to maintain a rotating disk calculated? The torque needed to maintain a rotating disk can be calculated by multiplying the force applied to the disk by the radius at which the force is applied. want to make something rotate. 4 N⋅s/m2 • A 120 mm disc rotates on a table separated by an oil film of 1. [5 Marks) Apr 30, 2011 · A uniform film of oil 0. 039N. Jun 11, 2017 · The required torque at the stepper appears to be just under 0. 95 * 10^-7 Newtons. 6 × 10–4 Nm. Why is a safety factor used in calculating required torque? The safety factor accounts for uncertainties and variations in the system's operational conditions, ensuring the selected components can handle unexpected Question: 1) The torque required to rotate a 6m diameter flat disc in air at 6. It must include the coeficient of friction between the surfaces of the disk/window as one of the variables. The disk is rotated steadily at angular velocity ohm. then from this value of ang. 537 N·m, determine the dynamic viscosity of the fluid. 4cm, height 1cm, weight 12g with a required torque of 622. Mar 30, 2015 · Point(c) is a going into the page and attached to the disc, Point(c) applies a torque($\tau$) to the disc, and it starts to rotate due to that torque. And if point(c) was move from the center to the far left like so: The disc will still rotate, around point(c). This is known as Question: Use the image to determine the answer(s). The thicker the fluid, the more torque will be necessary to achieve the same rate of rotation. Here, the required angular acceleration is positive for 1. Assume the velocity gradient in the oil film to be linear • μ = . ñ ì poise (Ans. Find the shear stress at r=1. Question: Determine the torque T, required to rotate the disk with a constant angular velocity of w=30 rad/sec. A oil film of viscosity mu and thickness lies between a solid wall and a circular disk, h < < R as in Fig. a) Calculate the coefficient of viscosity of a suitable liquid. If the torque required to rotate the disk at W = 900 rpm is 0. 3 rad/s is to be found by measuring the torque required to rotate a geometrically similar disc of 0. Mass of Drum: 13,500 lb Mass of Material inside: 13,700 lb Diameter of Drum: 38" Length of Drum: 297" Drum to Rotate at 10 rpm. Mar 3, 2012 · In summary, to rotate a disk or diameter 1. Jan 27, 2023 · For better understanding, consider a scenario where you have a small disk submerged in a viscous fluid like honey. Find the torque required to rotate one disc relative to the other at a steady speed of 400 rev/min if the oil has a viscosity of 0. Assume the velocity profile is linear, and μ = 0. First the 12. sm2. 428 N*s/m^2. A 120 mm disc rotates on a table separated by an oil film of 1. 5 seconds and negative for 1. 6 10* NM. b. 5" dia shaft. 18kg thank you The space between the disk and the solid boundary is1. Step by step solution 01 The torque τ required to rotate a disk of diameter D with angular velocity w in a fluid is a function of the density ρ and the viscosity μ of the fluid (torque has units of work) (a) Find a nondimensional relationship between these quantities. 428 N·s/m2 150 mm T Prob. It might accelerate very slowly however. Mar 3, 2012 #1 Mar 27, 2015 · I would like to calculate torque to rotate 1200 kg of mass which is attached in 1. Dec 2, 2014 · In summary, when calculating the torque required to rotate a disk at a constant speed, other factors to consider include air resistance, friction in the bearings, and other external forces. Jan 19, 2009 · how to determine the torque of a rotating disc in order to find the power of motor? there is a rotating disc, and a ball will pass through and launched by the rotating disc. 6 Newtons, the disk and rod assembly would need to be turned by 2. 13 mm thick separates two circular discs, each 150 mm diameter and mounted coaxially. 60 mm and is filled with oil with viscosity of 0. The disk is rotated at 22rads. 20 mm. Also, find the torque required to Oct 26, 2017 · It is a horizontal cylinder that will rotate through its central axis. Jul 23, 2014 · using the RPM, first calculate angular velocity using the formula (2*pi*RPM)/60. The torque required to rotate the disc in the opposite direction with the same angular speed in a time of 100 sec is approximately \(400\pi Nm\). s. where: τ is the torque (Nm) μ is the viscosity of the oil (Ns/m²) r is the radius of the disc (m) h is the thickness of the oil film (m) ω is the angular velocity of the disc (rad/s) Oct 3, 2024 · Acceleration torque is the additional torque required to bring the load from rest to its operating speed over a specific time. Friction in the bearings and the drive is negligible. Find the viscosity of oil if the torque required to rotate the disc at 60 r. Question: 1-45. 2m disc can be affected by factors such as the weight and diameter of the disc, the friction between the disc and the surface it is resting on, and the speed at which it is being turned. m is 3. 34 kg m 2; and a is angular acceleration. p. s/m² and the spacing y= 2 mm, what is the shear stress for the conditions noted in part (b)? (2 pt) (d) What torque is required to rotate the disk at a rate of 3 rad/s, with D= 10 cm, and with the same viscosity and conditions as in part (c)? (4 pt) Disk Oil --- sr D Jan 31, 2015 · In the context of rotating disks, torque is the force that is needed to maintain the disk's rotational motion. Sep 3, 2021 · This problem focuses on determining the torque the fluid exerts on the disk. Feb 3, 2021 · Assuming no friction, any torque will start the disc spinning. Noting that both velocity and shear stress vary with radius r, derive a formula for the torque M required to rotate the disk. lets consider a pulley drive system with a load force applied tangential to the disc. 5 seconds, assuming the disk (2 pt) (c) If the oil viscosity is 0. 14 Pa. 1-45 Oct 14, 2023 · To find the viscosity of the oil, we can use the formula for the torque required to rotate a disc in a viscous medium: τ = μ h 2 π r 3 ω. The oil has a thickness of 0. The radius of the disk is 9 cm . Without the ability to change the speed of a disc, it would be impossible for you to watch a movie on your DVD player. 5cm, where r isthe radial distance from the center of the disc. The torque required will be that force times the radial distance. Determine the torque T required to rotate the disk with a constant angular velocity of ω = 30 rad/s. the initial speed is 20m/s, and i could determine the rpm from here. Neglect bearing frication. velocity calculate the angular acceleration using the formula. Shaft is supported by 2 bearings at its end. Use worst case values to estimate the torques. The weight of the disk may also impact the required torque, but this will depend on the specific situation and should be evaluated accordingly. W a. A rotating disk viscometer has a radius, R = 50 mm, and a clearance, h = 1 mm, as shown in the figure. 53 kg cylinder with radius 144 mm must be accelerated to 5 RPM in 5 seconds. You can use physics to calculate the amount of torque needed to accelerate (or decelerate) the speed of a spinning disc. tax rnh znv jquoj srjgp mugo wgpo vyuanh afdrxus gcitboh